Lecture 16

Conditional Distributions and Independence


Grace Tompkins

Last modified — 13 Nov 2026

Learning Outcomes

By the end of this lecture, students are anticipated to be able to:

  • Calculate and utilize conditional distributions

  • Determine whether random variables are independent based on their conditional and joint distributions

1 Conditional Distributions

Conditioning on Discrete RVs

Let \(Y\) be a random variable, where \(X\) is a discrete random variable. Suppose that \(\mathbb{P}(X = x) >0\) for some \(x\). Then the conditional distribution of \(Y\) given \(X = x\) assigns to each set \(A \subset {\mathbb{R}}\) the probability \[\mathbb{P}(Y \in A \ \vert\ X = x) = \frac{\mathbb{P}(Y \in A, X = x)}{\mathbb{P}(X = x)}.\]

Here, we do not specify whether \(Y\) is continuous or discrete.

Conditioning on Discrete RVs

If \(X\) and \(Y\) are both discrete random variables, then the conditional PMF of \(Y\) given \(X = x\) is defined by \[p_{Y|X}(y \ \vert\ x) = \frac{\mathbb{P}(Y = y, X = x)}{\mathbb{P}(X = x)} = \frac{p_{X,Y}(x,y)}{p_X(x)}.\]

Note: we can rearrange this equation to get \[p_{X,Y}(x,y) = p_{Y|X}(y \ \vert\ x)p_X(x)\]

Conditioning on Discrete RVs

  • Let \(X\) and \(Y\) be the results of rolling two fair 6-sided dice.
  • Let \(V = X + Y\) and \(W = \max\{X, Y\}\).

The joint PMF of \(W\) and \(V\) is

\(W\ \backslash\ V\) 2 3 4 5 6 7 8 9 10 11 12
1 1/36 0 0 0 0 0 0 0 0 0 0
2 0 2/36 1/36 0 0 0 0 0 0 0 0
3 0 0 2/36 2/36 1/36 0 0 0 0 0 0
4 0 0 0 2/36 2/36 2/36 1/36 0 0 0 0
5 0 0 0 0 2/36 2/36 2/36 2/36 1/36 0 0
6 0 0 0 0 0 2/36 2/36 2/36 2/36 2/36 1/36

To condition on \(W\), we look at a particular row, while to condition on \(V\), we look at a particular column. Then renormalize by the sum of the row/column.

Conditioning on Discrete RV

\(W\ \backslash\ V\) 2 3 4 5 6 7 8 9 10 11 12
1 1/36 0 0 0 0 0 0 0 0 0 0
2 0 2/36 1/36 0 0 0 0 0 0 0 0
3 0 0 2/36 2/36 1/36 0 0 0 0 0 0
4 0 0 0 2/36 2/36 2/36 1/36 0 0 0 0
5 0 0 0 0 2/36 2/36 2/36 2/36 1/36 0 0
6 0 0 0 0 0 2/36 2/36 2/36 2/36 2/36 1/36

Given the above table, what is \(\mathbb{P}(W = 5 \ \vert\ V = 8)\)

Conditioning on Discrete RVs

Conditioning on Continuous RVs

If \(X\) and \(Y\) are jointly absolutely continuous random variables, then the conditional density of \(Y\) given \(X = x\), is the function \[f_{Y|X}(y \ \vert\ x) = \frac{f_{X,Y}(x,y)}{f_X(x)},\] valid for any \(y\in{\mathbb{R}}\), and all \(x\) such that \(f_X(x) > 0\).

Note: we can rearrange this equation to get \[f_{X,Y}(x,y) = f_{Y|X}(y \ \vert\ x)f_X(x)\]

Conditioning on Continuous RVs

Let \(X\) and \(Y\) be jointly absolutely continuous random variables with joint PDF \(f_{X,Y}\). The conditional distribution of \(Y\) given \(X = x\) assigns to each set \(A \subset {\mathbb{R}}\) the probability \[\mathbb{P}(a \le Y \le b \ \vert\ X = x) = \int_a^b f_{Y|X}(y\ \vert\ x)\, \mathsf{d}y,\] valid for all \(x\) such that \(f_X(x) > 0\).

Conditioning on Continuous RVs

Let \(X\) and \(Y\) be jointly continuous random variables with joint PDF \[f_{X,Y}(x,y) = \frac{1}{x} e^{-x} I_{\{0 \le y \le x\}}(x,y).\]

  1. Find the marginal PDF of \(X\). What distribution does \(X\) have?
  2. Find the conditional PDF of \(Y\) given \(X = x\). What distribution does \(Y \ \vert\ X\) have?

Conditioning on Continuous RVs

Conditioning on Continuous RVs

Let \(X\) and \(Y\) be independent with \(X \sim {\mathrm{Exp}}(1)\) and \(Y\sim {\mathrm{Exp}}(2)\). Let \(S = X + Y\). Find the conditional density \(f_{X|S}(X = x | S = s)\)

Conditioning on Continuous RVs

Conditioning on Continuous RVs

Conditional Distributions and Independence

Recall that if \(X\) and \(Y\) are independent, we have: \(\mathbb{P}(Y \in A \ \vert\ X = x) = P(Y \in A)\) This implies:

\[p_{Y|X}(y \ \vert\ x) = p_Y(y)\] and \[f_{Y|X}(y \ \vert\ x) = f_Y(y)\] when \(X\) and \(Y\) are independent.

Conditional Distributions and Independence

Heuristics Types of Distributions of Random Variables

  • Suppose that \(X\) and \(Y\) have a joint distribution \(\mathbb{P}(X \in A, Y \in B)\).
  • We can find the joint CDF, PMF, or PDF of \(X\) and \(Y\).
  • The marginal distribution of \(X\) is the distribution of \(X\) when we “ignore” \(Y\).
  • The conditional distribution of \(X\) given \(Y = y\) is the distribution of \(X\) when we “fix” \(Y\) to be \(y\).
  • The marginal comes from “summing out” or “integrating out” the other variable along the rows or columns of the table.
  • The conditional comes from “dividing out” the other variable. Fix a row or a column, and then renormalize (divide out).
  • When we say \(Y\ \vert\ X=x\), we usually specify a formula. Meaning, we write down a function that gives the conditional PMF or PDF of \(Y\) given \(X = x\) for all \(x\) such that \(p_X(x) > 0\) or \(f_X(x) > 0\). Renormalizing the row of a table gives the conditional PMF for a specific value of \(x\).

Checkpoint 5

You may have:

  • HANDWRITTEN Cheat Sheet

  • Non-graphing, non-programmable calculator

  • Writing materials

Phones and laptops put away, please! You can have 20 minutes.

Reminders:

  • No class Monday November 9. No checkpoint on Friday, either!

  • Midterm 2 is on Friday November 20